SOLUTION: I got stuck and I don't know what to do F(x) = x^2+2x-35 ------ -x^2+3x+10 This is what I did F(x) = x^2+2x-35 -> (x^2+7)(-5x-35) -> x(x+7)-5(x+7) -> (x+7) (x-5) ------

Algebra ->  Finance -> SOLUTION: I got stuck and I don't know what to do F(x) = x^2+2x-35 ------ -x^2+3x+10 This is what I did F(x) = x^2+2x-35 -> (x^2+7)(-5x-35) -> x(x+7)-5(x+7) -> (x+7) (x-5) ------      Log On


   



Question 815560: I got stuck and I don't know what to do
F(x) = x^2+2x-35
------ -x^2+3x+10

This is what I did F(x) = x^2+2x-35 -> (x^2+7)(-5x-35) -> x(x+7)-5(x+7) -> (x+7) (x-5)
------------------------------ -x^2+3x+10 -> (x^2-2x)(5x+10) -> x(x-2)5(x+2)
This is where I am and I know this has to be wrong and I'm hoping you can help me out on this and fix what I did (it's the bottom part I don't get I know I did the top part right )
Please and thank you

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
x^2+2x-35 = (x+7)(x-5) |Yes
-x^2+3x+10 = (-x +5)(x + 2)= -(x-5)(x+2)
IF this was Your problem