SOLUTION: How much of a 70%-alcohol solution must be mixed with 50 gallons of a 23%-alcohol solution to obtain a solution that is 60% alcohol?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How much of a 70%-alcohol solution must be mixed with 50 gallons of a 23%-alcohol solution to obtain a solution that is 60% alcohol?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 815426: How much of a 70%-alcohol solution must be mixed with 50 gallons of a 23%-alcohol solution to obtain a solution that is 60% alcohol?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
.7x+.23*50=.6*(x+50)
0.7x+11.5 = 0.6 x+30.
0.1 x=18.5
x = 185.
since 60 is so close to 70 you know it is going to be a lot