SOLUTION: Runner 1 ran: 4/x runner 2 ran: 5x runner 3 ran: (2x+2)/x^2 How much more did runner 3 run than runner 1 and 2 combined? PLease Help!

Algebra ->  Expressions-with-variables -> SOLUTION: Runner 1 ran: 4/x runner 2 ran: 5x runner 3 ran: (2x+2)/x^2 How much more did runner 3 run than runner 1 and 2 combined? PLease Help!      Log On


   

Question 815293: Runner 1 ran: 4/x
runner 2 ran: 5x
runner 3 ran: (2x+2)/x^2
How much more did runner 3 run than runner 1 and 2 combined? PLease Help!
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
"1 and 2 combined" translates into "add runner 1's and runner 2's distances:
4%2Fx%2B5x
To add we must have the same denominator:
4%2Fx%2B%285x%2F1%29%28x%2Fx%29
4%2Fx%2B5x%5E2%2Fx%29
%284%2B5x%5E2%29%2Fx%29

"much more did runner 3 run than runner 1 and 2 combined" translates into "subtract runner 3's distance minus ... runner 1 and 2 combined":
%282x%2B2%29%2Fx%5E2-%284%2B5x%5E2%29%2Fx%29
Again we need the same denominator to subtract:
%282x%2B2%29%2Fx%5E2-%28%284%2B5x%5E2%29%2Fx%29%28x%2Fx%29
%282x%2B2%29%2Fx%5E2-%284x%2B5x%5E3%29%2Fx%5E2
Subtracting:
%28-2x%2B2-5x%5E3%29%2Fx%5E2