SOLUTION: if x=1+i,where i=(-1)^1\2,then x^5 is?please tell the answer
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Question 815161
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if x=1+i,where i=(-1)^1\2,then x^5 is?please tell the answer
Answer by
Alan3354(69443)
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if x=1+i,where i=(-1)^1\2,then x^5 is?please tell the answer
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x^2 = (1+i)^2 = 1 + 2i - 1 = 2i
x^4 = (2i)^2 = -4
x^5 = -4*(1+i) = -4-4i
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Is there some reason you couldn't do that?