SOLUTION: A motorboat traveling with the current went 35 mi in 3.5 h.Traveling against the current, the boat went 12 mi in 3h.Find the rate of the boat in calm water and the rate of the curr
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Question 815142: A motorboat traveling with the current went 35 mi in 3.5 h.Traveling against the current, the boat went 12 mi in 3h.Find the rate of the boat in calm water and the rate of the current. Answer by mananth(16946) (Show Source):
boat speed =x mph
current speed =y mph
against current 3 hours
with current 3.5 hours
Distance against 12 miles distance with 35 miles
t=d/r against current -
12.00 / ( x - y )= 3.00
3.00 ( x - y ) = 3.50
3.00 x - 3.00 y = 12.00 ....................1
35.00 / ( x + y )= 3.50
3.50 ( x + y ) = 35.00
3.50 x + 3.50 y = 35.00 ...............2
Multiply (1) by 3.50
Multiply (2) by 3.00
we get
10.50 x + -10.50 y = 42.00
10.50 x + 10.50 y = 105.00
21.00 x = 147.00
/ 21.00
x = 7.00 mph
plug value of x in (1) y
3.00 x -3.00 y = 12.00
21.00 -3.00 -21.00 = 12.00
-3.00 y = 12.00
-3.00 y = -9.00 mph
y = 3.00
boat speed 7.00 mph
current speed 3.00 mph