SOLUTION: Transform equation to standard form and find center and radius, show work. x^2+y^2+12x+8y−101=0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Transform equation to standard form and find center and radius, show work. x^2+y^2+12x+8y−101=0       Log On


   

Question 815047: Transform equation to standard form and find center and radius, show work.
x^2+y^2+12x+8y−101=0
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
(x+6)^2+(y+4)^2=153
circle
center | (-6, -4)
radius | 3 sqrt(17)=12.3693
diameter | 6 sqrt(17)=24.7386
area | 153 pi=480.664
perimeter | 6 sqrt(17) pi=77.7187
curvature | 1/(3 sqrt(17))=0.0808452