SOLUTION: find the center and the radius of a circle with the equation (6-x)^2+(y+5)^2=37

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Question 815029: find the center and the radius of a circle with the equation
(6-x)^2+(y+5)^2=37
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

find the center and the radius of a circle with the equation 

(6-x)^2+(y+5)^2=37

Standard Form of an Equation of a Circle is %28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2 

where Pt(h,k) is the center and r is the radius

 (6-x) = -(x-6)  and [-(x-6)]^2 = (x-6)^2

(x-6)^2+(y+5)^2=37

 C(6,-5)  ,     r = sqrt%2837%29