SOLUTION: This uses the quotient property. Use log5(2)=.4307 and log5(3)=.6826 to approximate log5(54) ...all numbers in parenthesis are exponents and the equal signs are the squigly ones

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: This uses the quotient property. Use log5(2)=.4307 and log5(3)=.6826 to approximate log5(54) ...all numbers in parenthesis are exponents and the equal signs are the squigly ones      Log On


   

Question 81501This question is from textbook Glencoe Mathmatics Algebra 2
: This uses the quotient property.
Use log5(2)=.4307 and log5(3)=.6826 to approximate log5(54) ...all numbers in parenthesis are exponents and the equal signs are the squigly ones. This question is from textbook Glencoe Mathmatics Algebra 2

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
log%285%2C54%29
log%285%2C2%2A27%29
log%285%2C2%2A3%5E3%29+
log%285%2C2%29%2Blog%285%2C3%5E3%29+
log%285%2C2%29+%2B+3%2Alog%285%2C3%29+

Now, substitute in the values that are given: log%285%2C2%29=.4307 and log%285%2C3%29=.6826+

log%285%2C2%29+%2B+3%2Alog%285%2C3%29+
+.4307+%2B+3%2A.6826+
2.4785

Of course, you can always check this answer by calculating
log%285%2C54%29+=+%28ln+54%29%2F%28ln5%29+

The result is approximately the same!

R^2 at SCC