SOLUTION: What is the altitude of an equilateral triangle whose perimeter is 6 to the square root of 6

Algebra ->  Triangles -> SOLUTION: What is the altitude of an equilateral triangle whose perimeter is 6 to the square root of 6      Log On


   

Question 814999: What is the altitude of an equilateral triangle whose perimeter is 6 to the square root of 6
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
Difficult to draw within the system, but I'll describe it:

Draw a triangle, equilateral; form altitude and call this length h. Label each side of the equilateral triangle as x. The altitude reaching the bottom or base side intersects this side to form two lengths x/2. Also, the altitude, h, cuts the triangle into two congruent 30-60-90 triangles. You can use pythagorean theorem for ONE of these triangles ( or the other as well).

You have h%5E2%2B%28x%2F2%29%5E2=x%5E2 and because of the given information about perimeter, 3x=6.

That is enough developed information. Can you solve for h?



-------------------------------
After just solving for h myself, I wonder, why do you want the answer to the nearest square root of 6 and not to nearest square root of 3 ?
..
..
In other words, why do you want h=%28sqrt%282%29%2F2%29sqrt%286%29?