SOLUTION: Find three consecutive odd positive integers such that two times the sum of all three is seven more than the product of the first and second integers.

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Question 814853: Find three consecutive odd positive integers such that two times the sum of all three is seven more than the product of the first and second integers.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let the integers be x, x+2, x+4.
2(x+x+2+x+4)=x(x+2)+7
2(3x+6)=x^2+2x+7
6x+12=...
x^2-4x-5=0
(x-5)(x+1)=0
x=5
x+2=7
x+4=9
.
Ed