SOLUTION: can someone please check this for me? {{{x^2-11x+24 = 0}}} {{{x=((-(-11))+-sqrt(11^2-4*1*24))/(2*1)}}} {{{x=(11+5)/(2*1)}}} {{{x=16/2=8}}} {{{x=6/2=3}}} {{{x=8}}},{{{3}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: can someone please check this for me? {{{x^2-11x+24 = 0}}} {{{x=((-(-11))+-sqrt(11^2-4*1*24))/(2*1)}}} {{{x=(11+5)/(2*1)}}} {{{x=16/2=8}}} {{{x=6/2=3}}} {{{x=8}}},{{{3}}}      Log On


   

Question 81445: can someone please check this for me?
x%5E2-11x%2B24+=+0
x=%28%28-%28-11%29%29%2B-sqrt%2811%5E2-4%2A1%2A24%29%29%2F%282%2A1%29
x=%2811%2B5%29%2F%282%2A1%29
x=16%2F2=8
x=6%2F2=3
x=8,3
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

can someone please check this for me?
x%5E2-11x%2B24+=+0
x=%28%28-%28-11%29%29%2B-sqrt%2811%5E2-4%2A1%2A24%29%29%2F%282%2A1%29
x=%2811%2B5%29%2F%282%2A1%29
x=16%2F2=8
x=6%2F2=3
x=8,3
All you have to do to check is to substitute
them in the original:
x%5E2-11x%2B24+=+0
%288%29%5E2-11%288%29%2B24+=+0
64-88%2B24%7D+=+0
0+=+0
That one checks.
x%5E2-11x%2B24+=+0
%283%29%5E2-11%283%29%2B24+=+0
9-33%2B24%7D+=+0
0+=+0

That one checks too. So you are right.
Edwin