Question 814184: Emma paid the $10.36 bill for her lunch with 232 coins consisting of pennies, nickels, dimes. If the number of nickels plus the number of dimes was equal to the number of pennies, then how many coins of each type did she use?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! p + n + d = 232
n + d = p
p + 5n + 10d = 1036
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p + 5n + 10d = 1036
n + d + 5n + 10d = 1036
6n + 11d = 1036
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p + n + d = 232
n + d + n + d = 232
2n + 2d = 232
n + d = 116
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n + d = p
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Answer 1:
p = 116
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n + d = 116
n = 116 - d
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6n + 11d = 1036
6(116 - d) + 11d = 1036
696 - 6d + 11d = 1036
5d = 340
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Answer 2:
d = 68
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Final answer:
p = 116
n = 48
d = 68
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