SOLUTION: Please help me solve: find the values of t, with 0 is less than or equal to t which is less than or equal to 2 pie, such that 2 sin (t) cos (t) = cos^2 (t) - sin^2 (t)
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-> SOLUTION: Please help me solve: find the values of t, with 0 is less than or equal to t which is less than or equal to 2 pie, such that 2 sin (t) cos (t) = cos^2 (t) - sin^2 (t)
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Question 814022: Please help me solve: find the values of t, with 0 is less than or equal to t which is less than or equal to 2 pie, such that 2 sin (t) cos (t) = cos^2 (t) - sin^2 (t) Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the values of t, for interval [0,2π] such that 2 sin (t) cos (t) = cos^2 (t) - sin^2 (t)
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2sin(t)cos(t)=cos^2(t)-sin^2(t)
sin(2t)=cos(2t)
sin(2t)/cos(2t)=1
tan(2t)=1
2t=π/4,7π/4
t=π/8,7π/8
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