SOLUTION: Find three consecutive numbers even integers such that three times the first plus six times the second is equal to ten times the second.

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Question 813818: Find three consecutive numbers even integers such that three times the first plus six times the second is equal to ten times the second.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

3(x-2) + 6x = 10x
3x - 6 + 6x = 10x
9x - 6 = 10x
-6 = x

The integers are -8, -6, and -4.