Question 813747: Hello, I was wondering if you could explain how to Write the equation of a line parallel to the given line but passing through the given point.
y=-2x-4; (1,3)? so far I have Y=-2x-4; (1, 3)
m= 1, (1, 3)
y-y1=m(x-x1)
y-3=1(x-1)
y-3=x-1
y=x+4
I am not sure if I have done this right or not.
Thank you
Found 2 solutions by richwmiller, josgarithmetic:
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! m=-2
y=mx+b
the slope will be the same
The slope of y=-2x-4 is -2
plug it in.
y=-2x+b
now plug in x and y 1 and 3
3=-2+b
solve for b
5=b
now plug in 5 for b
y=-2x+5
Answer by josgarithmetic(39620)  (Show Source):
You can put this solution on YOUR website! Line y=-2x-4, want line parallel to it, passing through (1,3).
Given line is in slope-intercept form, indicating slope is -2. The slope of the line we want is also  .
You have chose to continue the solution using Point-Slope form for a line, so I will do so also.
You already know that m is for slope. Your point ( , ) is the point (1,3). You must KNOW now that m=-2. Substitute and simplify:
 ---------Your Answer.
PARALLEL, PARALLEL, PARALLEL, PARALLEL,... Same Slope!
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