SOLUTION: The number of trout in a breeding pond is given by, 1400/1+5e^-0.09t where t is the number of months that have passed since the pond was stocked with trout. How many trout were

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Question 813735: The number of trout in a breeding pond is given by, 1400/1+5e^-0.09t where t is the number of months that have passed since the pond was stocked with trout.
How many trout were in the pond immediately after it was stocked?
How many trout were in the pond 1 year after it was stocked?
what will happen to the trout population as t increases without bound?

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The number of trout in a breeding pond is given by, Assume it's:
f(t) = 1400%2F%281%2B5e%5E%28-0.09t%29%29
where t is the number of months that have passed since the pond was stocked with trout.
:
How many trout were in the pond immediately after it was stocked?
Then t=0, e^0 = 1, therefore
f(t) = 1400%2F6
f(t) ~ 233 trout
:
How many trout were in the pond 1 year after it was stocked?
f(t) = 1400%2F%281%2B5e%5E%28-0.09%2A12%29%29
f(t) = 1400%2F%281%2B5%28.34%29%29
f(t) = 1400%2F2.7
f(t) = 519 trout
:
what will happen to the trout population as t increases without bound?
Eventually 5e becomes so close to 0, it will level off at around 1400 trout,
t = 100 months = 1399 trout