Question 813724: Greetings!
I certainly could you use expertise in solving the following problem:
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range.
x = -2y2 + 2y - 3
Thank you in advance for your help!
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range.
x = -2y2 + 2y - 3
complete the square:
x=-2(y^2-y+1/4)+1/2-3
x=-2(y-1/2)^2-5/2
(y-1/2)^2=-(1/2)(x+5/2)
This is a parabola that opens leftward:
Its basic form of equation: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex.
For given parabola:
4p=1/2
vertex:(-5/2,1/2)
axis of symmetry: y=1/2
domain: (-∞,5/2]
range: (-∞,∞)
|
|
|
