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Question 813635: Find two consecutive even integers such that twice the smallest one is 26 less than thrice the greatest one
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! m = n + 2
2n = 3m - 26
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2n = 3m - 26
2n = 3(n + 2) - 26
2n = 3n + 6 - 26
-n = -20
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n = 20
m = 22
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