SOLUTION: from 4 feet above the ground, Maya throws a ball upward with the velocity of 18 feet per second. The height h(t) of the ball t seconds after Maya throws the ball given by h(t)=-16t

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Question 813591: from 4 feet above the ground, Maya throws a ball upward with the velocity of 18 feet per second. The height h(t) of the ball t seconds after Maya throws the ball given by h(t)=-16t^2+18+4. Find the maximum height reached by the ball and the time that this height is reached
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Your equation is wrong
h(t)=-16t^2+18+4
should be
h(t)=-16t^2+18t+4
You want the vertex
x will be t
and y will be h(t)
vertex | (9/16, 145/16)=(0.5625, 9.0625)