SOLUTION: Determine the type of curve represented by the equation. Find the foci and vertices (if any). {{{x=y^2-16y}}}

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Question 813416: Determine the type of curve represented by the equation. Find the foci and vertices (if any).
x=y%5E2-16y
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
Here is SOME of the information but not all.

Parabola with symmetry axis parallel to the x-axis, opening to the right. You can Complete the Square for y to put this into standard form and read the vertex directly from the equation. The term to complete the square is %2816%2F2%29%5E2=64.

x=y%5E2-16y%2B64-64
highlight%28x=%28y-8%29%5E2-64%29
Vertex would be (-64,8)

For finding focus, study what your textbook discusses, and also you could use:
http://en.wikipedia.org/wiki/Parabola and check carefully the section called, "Equation in Cartesian Coordinates".