SOLUTION: Find 3 consecutive positive integers such that the product of the first and the third is 29 more than the second. Please respond!!! Thank you!:)

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find 3 consecutive positive integers such that the product of the first and the third is 29 more than the second. Please respond!!! Thank you!:)      Log On


   



Question 813188: Find 3 consecutive positive integers such that the product of the first and the third is 29 more than the second. Please respond!!! Thank you!:)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let 3 consecutive positive integers be:
x-first,
%28x%2B1%29-second,and
%28x%2B2%29-third
if the product of the first and the third is 29 more than the second, then we have
x%28x%2B2%29=%28x%2B1%29%2B29.....solve for x
x%5E2%2B2x=x%2B1%2B29
x%5E2%2B2x=x%2B30
x%5E2%2B2x-x-30=0
x%5E2%2Bx-30=0.........write x as 6x-5x
x%5E2%2B6x-5x-30=0.....group
%28x%5E2%2B6x%29-%285x%2B30%29=0
x%28x%2B6%29-5%28x%2B6%29=0
%28x-5%29%28x%2B6%29+=+0
solutions:
if %28x-5%29++=+0=>x=5
+%28x%2B6%29+=+0=>x=-6.....since we need consecutive positive integers, disregard this solution
so, your consecutive positive integers are:
x=5
x%2B1=6
x%2B2=7