SOLUTION: Find three concecutive odd integers such that the largest decreased by twice the second is 46 less than the smallest

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Question 813186: Find three concecutive odd integers such that the largest decreased by twice the second is 46 less than the smallest
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

x+2 - 2x = (x-2) - 46
-x + 2 = x - 48
50 = 2x
x = 25

The integers are 23, 25, and 27.