Question 813069: solve
2A+T=3T^2 for T
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! 2A + t = 3t^2
2A = 3t^2 - t
A = (3/2)t^2 + (-1/2)t + 0
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the above quadratic equation is in standard form, with a=1.5, b=-0.5, and c=0
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to find the max or min of A(t) and the roots of A(t), plug this:
1.5 0.5 0
into this: https://soeet.com/math/quadratic-equation-solver.php
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Answer 1:
the minimum point of the above quadratic equation is: ( -0.166666667, -0.0416666667 )
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Answer 2:
the two roots (x-intercepts) of the above quadratic equation are:
root1: 0
root2: -0.333333333
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