Question 813046: One type of motor requires a mixture of oil and gasoline in a ratio of 1 to 15 (that is, 1 part of oil to 15 parts of gasoline). How many liters of each area contained in 20-liter mixture?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! a = oil
g = gas
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1/15 = a/g
15 = g/a
15a = g
g + a = 20
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g + a = 20
15a + a = 20
16a = 20
a = 5/4
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a = 1.25 liters
g = 18.75 liters
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check:
18.75/1.25 = 15/1
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