SOLUTION: Sarim has $1 in coins. One-fifth of the coins are dimes, two-fifteenths of the coins are nickels, and two-thirds are pennies. Tell how many of each coin he has.

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Question 812988: Sarim has $1 in coins. One-fifth of the coins are dimes, two-fifteenths of the coins are nickels, and two-thirds are pennies. Tell how many of each coin he has.
Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
10d+5n+p=100
p+n+d=c
c/5=d,
2/15c=n,
2/3c=p
c = 30, d = 6, n = 4, p = 20

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Sarim has $1 in coins 0r 100¢ 

One-fifth of the coins are dimes,  30%2F5+=+6

two-fifteenths of the coins are nickels, %282%2F15%2930+=+4

and two-thirds are pennies %282%2F3%29+30+=+20

Let x represent the total number of coins

Question states***

%28x%2F5%2910+%2B+%282x%2F15%295+%2B+%282x%2F3%29+=+100

Solving for x 

+2x+%2B+%282%2F3%29x+%2B+%282%2F3%29x+=+100

  6x + 2x + 2x = 300

       10x = 300

          x+=+highlight%2830%29



CHECKING our Answer***

   60¢ + 20¢ + 20¢ = 100¢