SOLUTION: how to find the radius and the center of circle given this equation; x squared - y squared - 6x-4y-3=0 (x squared - 6x)+6 (y squared- 4y)=3

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: how to find the radius and the center of circle given this equation; x squared - y squared - 6x-4y-3=0 (x squared - 6x)+6 (y squared- 4y)=3       Log On


   

Question 812792: how to find the radius and the center of circle given this equation;
x squared - y squared - 6x-4y-3=0
(x squared - 6x)+6 (y squared- 4y)=3
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
You'll need to re-post your question. The equation you posted here is a hyperbola, not a circle.