SOLUTION: write a finite arithmetic series that has a sum of 245, has 10 terms, and has a common difference not equaling 0
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-> SOLUTION: write a finite arithmetic series that has a sum of 245, has 10 terms, and has a common difference not equaling 0
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Question 812730: write a finite arithmetic series that has a sum of 245, has 10 terms, and has a common difference not equaling 0 Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Sn = n/2( 2a+(n-1)d)
S10 = 10/2(2a+9d)
245=5(a+9d).................(1)
T10= a+9d
substitute in (1)
S10= 5*t10
245/5 = t10
49 =t10...........................(2)
S10-S9=t10
245-s9=45
S9= 200
200= 9/2(2a+8d)
200=9a+36d.......................(3)
solve equation (1) & (3)
245=10a+45d
200=9a+36d
you will get a=4
and d= 41/9
4
8.56
13.11
17.67
22.22
26.78
31.33
35.89
40.44
45
Add them up you get 245
