SOLUTION: Find any real numbers that satisfy the following equation. X^2=2(x+3) Enter the exact answers in increasing order.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Find any real numbers that satisfy the following equation. X^2=2(x+3) Enter the exact answers in increasing order.       Log On


   

Question 812723: Find any real numbers that satisfy the following equation.
X^2=2(x+3)
Enter the exact answers in increasing order.
Found 2 solutions by stanbon, erica65404:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find any real numbers that satisfy the following equation.
X^2=2(x+3)
Enter the exact answers in increasing order.
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x^2 -2x -6 = 0
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x = [2 +- sqrt(4-4*-6)]/2
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x = [2 +- sqrt(28)]/2
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x = [2+2sqrt(7)]/2 or x = [2-2sqrt(7)]/2
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x = 1-sqrt(7) ; x = 1+sqrt(7)
===============================================
Cheers,
Stan H.

Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2=2%28x%2B3%29
x%5E2=2x%2B6
x%5E2-2x-6=0
a=1 b=-2 c=-6
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%2A1%2A%28-6%29+%29%29%2F%282%2A1%29+
x+=+%282+%2B-+sqrt%28+28+%29%29%2F%282%29+
x+=+%282+%2B-+2%2Asqrt%287%29%29%2F%282%29
x+=+%281+%2B-+sqrt%287%29%29
x+=+1-sqrt%287%29
x+=+1%2Bsqrt%287%29