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| Question 812523:  A roofer requires 14 h to shingle a roof. After the roofer and an apprentice work on a roof for 7 h, the roofer moves on to another job. The apprentice requires 7 more hours to finish the job. How long would it take the apprentice, working alone, to do the job?
 
 Answer by TimothyLamb(4379)
      (Show Source): 
You can put this solution on YOUR website! rate = time/job time = rate * job
 job = time/rate
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 r = roofer work rate
 a = apprentice work rate
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 r = 14 hr/job
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 use equation:
 job = time/rate
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 7/(r + a) + 7/a = 1 job
 7/(14 + a) + 7/a = 1 job
 7a/(a(14 + a)) + 7(14 + a)/(a(14 + a)) = 1 job
 7a/(aa + 14a) + 7(14 + a)/(aa + 14a) = 1 job
 7a/(aa + 14a) + (7a + 98)/(aa + 14a) = 1 job
 (14a + 98)/(aa + 14a) = 1 job
 14a + 98 = aa + 14a
 14a + 98 = aa + 14a
 aa = 98
 a = sqrt(98)
 a ~= 9.8995 hr/job
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