Question 812194: You must form an equation and solve it to the remaining application problems. Oh, and don't forget to clearly define your variable(s). Please write your answers in complete sentences.
A rectangular mirror has an area of 10 FT^2 (square), and it is 1.5 ft longer than it is wide. Find the dimensions of the mirror.
A=(L)(W), so
10=W+
Answer by CubeyThePenguin(3113) (Show Source):
You can put this solution on YOUR website! w = width
area = (length)(width)
10 = (w)(w + 1.5)
10 = w^2 + 1.5w
20 = 2w^2 + 3w
0 = 2w^2 + 3w - 20
0 = (2w - 5)(w + 4)
w = 5/2, w = -4
Distance has to be positive, so the mirror is 5/2 = 2.5 ft wide and 4 ft long.
|
|
|