SOLUTION: I have a problem trying to solve this logarithm. log base 3 (x^2+1)=4 log3(x^2+1)=4. According to the log rules of logb(+/-) it can be rearranged unless it's multiplication and di

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I have a problem trying to solve this logarithm. log base 3 (x^2+1)=4 log3(x^2+1)=4. According to the log rules of logb(+/-) it can be rearranged unless it's multiplication and di      Log On


   

Question 811931: I have a problem trying to solve this logarithm. log base 3 (x^2+1)=4
log3(x^2+1)=4. According to the log rules of logb(+/-) it can be rearranged unless it's multiplication and division, but this has something in the parentheses so how would I go about solving this?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
log%283%28x%5E2%2B1%29%29 = 4
The exponent equiv of logs
(x^2+1) = 3%5E4
x^2 + 1 = 81
x^2 = 81 - 1
x^2 = 80
x = sqrt%2882%29
x = sqrt%2816%2A5%29
x = 4sqrt%285%29