SOLUTION: Como resuelvo este sistema de ecuaciones utilizando el metodo de sustitucion? 2x+3y=7 x-4y=-2 Gracias!

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Question 811815: Como resuelvo este sistema de ecuaciones utilizando el metodo de sustitucion?
2x+3y=7
x-4y=-2
Gracias!

Found 2 solutions by TimothyLamb, richwmiller:
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
2x + 3y = 7
x - 4y = -2
---
2x + 3y = 7
(-2)x - (-2)4y = (-2)-2
-2x + 8y = 4
---
add (sumar)
2x + 3y = 7
-2x + 8y = 4
---
11y = 11
--
answer (resultado)
y = 1
x - 4y = -2
x - 4(1) = -2
x - 4 = -2
x = 2
---
(2, 1)
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Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x-4y=-2
x=4y-2
2*(4y-2)+3y=7
8y-4+3y=7
11y=11
y=1
x=4y-2
x=4-2
x=2
de nada