SOLUTION: I having trouble finding out whether these Quadratic Equations have one solution, two solutions, or no solution. One of the problems is x^2+7x+4=0 I am having problems with t

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I having trouble finding out whether these Quadratic Equations have one solution, two solutions, or no solution. One of the problems is x^2+7x+4=0 I am having problems with t      Log On


   

Question 811700: I having trouble finding out whether these Quadratic Equations have one solution, two solutions, or no solution.
One of the problems is x^2+7x+4=0
I am having problems with this.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2%2B7x%2B4=0+.....use quadratic formula

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+...in your case a=1,b=7 and c=4

x+=+%28-7+%2B-+sqrt%28+7%5E2-4%2A1%2A4+%29%29%2F%282%2A1%29+

x+=+%28-7+%2B-+sqrt%28+49-16+%29%29%2F2

x+=+%28-7+%2B-+sqrt%28+33+%29%29%2F2

x+=+%28-7+%2B-+5.75%29%2F2

solutions:
x+=+%28-7+%2B5.75%29%2F2
x+=+-1.25%2F2
x+=+-0.625
or
x+=+%28-7+-5.75%29%2F2
x+=+-12.75%2F2
x+=+-6.375