SOLUTION: Write an equation for a parabola with a vertex being (1,6) and x-intercepts being (-3,0) and (5,0).

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Question 811552: Write an equation for a parabola with a vertex being (1,6) and x-intercepts being (-3,0) and (5,0).
Answer by lwsshak3(11628) About Me  (Show Source):
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Write an equation for a parabola with a vertex being (1,6) and x-intercepts being (-3,0) and (5,0).
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Given coordinates show that parabola has a vertical axis of symmetry:
Ita vertex form of equation: y=A(x-h)^2+k
Solving for A:
Using coordinates of one of given points(5,0)
0=A(5-1)^2+6
16A=-6
A=-6/16=-3/8
Equation:
y=(-3/8)(x-1)^2+6