Question 811541: I have a question i need to solve in my trig class
A ship sails N75degreesE for 90 nautical miles and then S10degreesW for 100 nautical miles. How far is the ship, then, from the starting point, and in what direction.
Could you help me out with this one
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A ship sails N75degreesE for 90 nautical miles and then S10degreesW for 100 nautical miles. How far is the ship, then, from the starting point, and in what direction.
Could you help me out with this one
-----------
End-point DATA::
x-coordinate: 90cos(75)+100cos(190) = -75.2
y-coordinate: 90sin(75)+100sin(190) = 69.6
--------
Distance from (0,0) starting point::
d = sqrt[75.2^2+69.6^2] = 102.4 nautica miles
--------
Direction:
arctan(69.6/-75.2) = 180-42.8 = 137.2 or W42.8degreesN
===================
Cheers,
Stan H.
|
|
|
