Question 811484: i cant find the solution can someone help me how to do this step by step
consider the line y=3/2x-4
Find the equation of the line that is parallel to this line and passes through the point (3,6)?
Find the equation of the line that is perpendicular to this line and passes through the point (3,6)?
Found 3 solutions by richwmiller, stanbon, rothauserc:
Answer by richwmiller(17219)   (Show Source):
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! consider the line y=3/2x-4
Find the equation of the line that is parallel to this line and passes through the point (3,6)?
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The given line has slope = 3/2
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Any line parallel to it must have slope = 3/2
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Form: y = mx + b
Solve for "b":
6 = (3/2)3 +b
12/2 - (9/2) = b
b = 3/2
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Equation:
y = (3/2)x + (3/2)
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Find the equation of the line that is perpendicular to this line and passes through the point (3,6)?
Any line perpendicular to the given line must have slope = -2/3
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Form: y = mx+b
Solve for "b":
6 = (-2/3)3 + b
b = 6 +2
b = 8
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Equation:
y = (-2/3)x + 8
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Cheers,
Stan H.
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Answer by rothauserc(4718)  (Show Source):
You can put this solution on YOUR website! given y = 3x/2 -4
1) parallel lines have the same slope, therefore a line parallel to the given line and passes through the point (3,6) is
6 = (3/2)*3 +c
12/2 = 9/2 +c
c = 3/2
y = 3x/2 +3/2
here is the graph of the parallel lines
2) the product of the slopes of two perpendicular lines is negative one, therefore
3/2 * m = -1 and m is -2/3, consider that this new line passes through point (3,6)
6 = (-2/3)*3 +c
c = 8
y = -2x/3 +8
here is the graph of the perpendicular lines
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