SOLUTION: L has intercept (0,2) and is perpendicular to the line with the equation 2x-3y=6 This equation has to be written with the equation of the line L satisfying the given geometric cond

Algebra ->  Graphs -> SOLUTION: L has intercept (0,2) and is perpendicular to the line with the equation 2x-3y=6 This equation has to be written with the equation of the line L satisfying the given geometric cond      Log On


   



Question 81142: L has intercept (0,2) and is perpendicular to the line with the equation 2x-3y=6 This equation has to be written with the equation of the line L satisfying the given geometric condition. This equation makes absolutly no sense.
- In planning for a new item, a manufacturer assumes that the number of items produced is x and the cost in dollars C of producing these items are related by a linear equation. Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce. Find the equation that relates C and x.
Thank you if you can help!!!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
L has intercept (0,2) and is perpendicular to the line with the equation
2x-3y=6 This equation has to be written with the equation of the line L satisfying the given geometric condition.
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The given equation can be written y=(2/3)x-2
It has slope 2/3.
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A perpendicular line will have slope -3/2
If it passes thru (0,2) that is the y-intercept.
So the equation you want is y=(-3/2)x+2
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- In planning for a new item, a manufacturer assumes that the number of items produced is x and the cost in dollars C of producing these items are related by a linear equation. Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce. Find the equation that relates C and x.
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You have two points: (100,10000) and (300,22000)
The slope = [22000-10000]/[300-100] = 12000/200 = 60
The equation form you want is y=mx+b where y=10000 when x=100 and slope=60.
So, 10000=60*100+b
b=4000
EQUATION:
Cost = 60x + 4000
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Cheers,
Stan H.