SOLUTION: Suppose y=5cos(5t+13)-4. In my answer i am suppose to answer with pi. what is the phase shift and horizontal shift
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Question 811158: Suppose y=5cos(5t+13)-4. In my answer i am suppose to answer with pi. what is the phase shift and horizontal shift Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose y=5cos(5t+13)−4. In my answer i am suppose to answer with pi. what is the phase shift and horizontal shift
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Form:: y = a*cos(b(x-c)) + d
Your problem:
y = 5cos(5(t+(13/5))
a = 5
b = 5
c = -13/5
d = -4
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phaseshift = c/b = -13/5 = -13/5
horizontal shift is phase shift.
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Cheers,
Stan H.
y = a·sin[b(x+c)] + d or y = a·cos[b(x+c)] + d
amplitude = |a|
period =
horizontal shift = |c| right if c negative, left if c positive
vertical shift = |d| up if d positive, down if d negative
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y = 5·cos(5t+13) − 4
y = 5·cos[5(t+)] - 5
a=5, b=5, c=, d = -5
amplitude = |5| = 5
period =
horizontal shift = |13/5| = 13/5 left since c positive
vertical shift = |-5| = 5 down since d negative
Edwin
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