SOLUTION: find three consecutive integers whose product is 85 larger than the cube of the smallest integer

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: find three consecutive integers whose product is 85 larger than the cube of the smallest integer      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 811157: find three consecutive integers whose product is 85 larger than the cube of the smallest integer
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find three consecutive integers whose product is 85 larger than the cube of the smallest integer
----------
1st: x-1
2nd: x
3rd: x+1
------------
Equation:
x(x^2-1) = (x-1)^3 + 85
-----
x^3 - x = x^3-3x^2+3x+84
-------
3x^2-4x-84 = 0
(x-6)(3x+14) = 0
-------
Positive solution::
x = 6
==================
1st: x-1 = 5
2nd: x = 6
3rd: x+1 = 7
=================
Cheers,
Stan H.
=================