SOLUTION: If sec t =5/4 with C(t) in quadrant 4, determine csc(t+pie).
Current progress:
As csc theta = 1/sin theta I created:
1/(t+pie)
Using the sine sum identity I came up with:
Algebra ->
Trigonometry-basics
-> SOLUTION: If sec t =5/4 with C(t) in quadrant 4, determine csc(t+pie).
Current progress:
As csc theta = 1/sin theta I created:
1/(t+pie)
Using the sine sum identity I came up with:
Log On
Question 811052: If sec t =5/4 with C(t) in quadrant 4, determine csc(t+pie).
Current progress:
As csc theta = 1/sin theta I created:
1/(t+pie)
Using the sine sum identity I came up with:
1/sin t x cos pie + sin pie x cos t
Now I am trying to use sec t to get to sin t but I am making little progress. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If sec t = 5/4 with C(t) in quadrant 4, determine csc(t+pie).
-------------------
Note: In QIV x is positve and y is negative
-----
Since sec(t) = r/x = 5/4, r = 5 and x = 4
Then y = sqrt[5^2-4^2] = -3
=========
Your Problem:
csc(t+pi) = -csc(t) = -y/r = 3/5
===================================
Cheers,
Stan H.
(