SOLUTION: An airplane flying into a headwind travels the 3000 mile distance between two cities in 6 hours and 15 minutes. On the return flight, with the wind, the trip was 5 hours. Find the

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Question 810796: An airplane flying into a headwind travels the 3000 mile distance between two cities in 6 hours and 15 minutes. On the return flight, with the wind, the trip was 5 hours. Find the speed of the plane in still air and the speed of the wind, assuming they are constant throughout the trip.
Solve using a system of equations.

Found 2 solutions by richwmiller, josgarithmetic:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
6.25*(x-w)=3000,
3000=5*(x+w)
w=60., x=540.

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Related to Wind__________speed_______________time____________distance
Into_____________________(r-w)_______________6%261%2F4_____3000
With_____________________(r+w)_______________5_______________3000

Variables assigned were r for speed without wind and w for speed of the wind.

Using R*T=D idea, R=D/T.

Related to Wind__________speed_______________time____________distance
Into_____________________(r-w=3000%2F%286%261%2F4%29)_______________6%261%2F4_____3000
With_____________________(r%2Bw=3000%2F5)_______________5_______________3000


The needed system of equations is shown under the "speed" column of the data table. The best way to handle them would be as r-w=480 and r%2Bw=600