SOLUTION: 2x+2y-z=3 3x-2y-2z=1 5x+y-3z=2

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Question 810774: 2x+2y-z=3
3x-2y-2z=1
5x+y-3z=2
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Too many = in the first equation. 2x+2y=z=3
assuming that the first = should be -
we have 2x+2y-z=3
x = 17, y = -2, z = 27
or if it should be +
2x+2y+z=3
x = 1, y = 0, z = 1