SOLUTION: A fence is to be built to enclose a rectangular area of 220 square feet. The fence along three sides is to be made of material that costs 6 dollars per foot, and the material for t

Algebra ->  Absolute-value -> SOLUTION: A fence is to be built to enclose a rectangular area of 220 square feet. The fence along three sides is to be made of material that costs 6 dollars per foot, and the material for t      Log On


   

Question 810724: A fence is to be built to enclose a rectangular area of 220 square feet. The fence along three sides is to be made of material that costs 6 dollars per foot, and the material for the fourth side costs 14 dollars per foot. Find the length L and width W (with W \leq L) of the enclosure that is most economical to construct.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The shorter measurement side should use the more expensive fence material. Let w%3CL and the dimensions are w and L.

2w%2B2L=220 and 14%2Aw%2B6%2Aw%2B2%2AL%2A6=c, where c = cost.

Simplify the c equation.
%2814%2B6%29w%2B12L=c
c=20w%2B12L
Solve the perimeter equation for either variable.
w+L=110
L=110-w
Substitute into the c equation.
c=20w%2B12%28110-w%29
c=20w%2B12%2A110-12w
c=8w%2B1320

The description of the problem is missing something.