SOLUTION: Vinod while driving his bike on a stretch having poles marked at equal distance crosses poles at every twenty seconds. If he increases his speed by x meters per second, he crosses
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Question 810716: Vinod while driving his bike on a stretch having poles marked at equal distance crosses poles at every twenty seconds. If he increases his speed by x meters per second, he crosses poles at every fifteen seconds. But if he increases his speed at y meters per second he crosses the poles at every tenth second. If Y - X = 40 meters per second, then what is the distance between two poles? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Vinod while driving his bike on a stretch having poles marked at equal distance crosses poles at every twenty seconds.
If he increases his speed by x meters per second, he crosses poles at every fifteen seconds.
But if he increases his speed at y meters per second he crosses the poles at every tenth second.
If Y - X = 40 meters per second, then what is the distance between two poles?
:
Let d = distance between the poles
Let s = original speed
:
original speed = 20 sec
:
1st increase = 15 sec
d = 15(s+x)
d = 15s + 15x
15s = d - 15x
s = - x
:
2nd increase = 10 sec
d = 10(s+y)
d = 10s + 10y
10s = d - 10y
s = - y
:
s=s therefore - y = - x
multiply by 30
3d - 30y = 2d - 30x
3d - 2d = 30y - 30x
d = 30(y-x)
we know that y-x = 40, therefore
d = 30(40)
d = 1200 meters between poles
