SOLUTION: Find the exact value of the expression. arccos (cos(-2pi/5))
Would x = -2pi/5? But then where is cos -2pi/5? It's not on the circle or chart...
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-> SOLUTION: Find the exact value of the expression. arccos (cos(-2pi/5))
Would x = -2pi/5? But then where is cos -2pi/5? It's not on the circle or chart...
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Question 810693: Find the exact value of the expression. arccos (cos(-2pi/5))
Would x = -2pi/5? But then where is cos -2pi/5? It's not on the circle or chart... Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find the exact value of the expression.
arccos (cos(-2pi/5))=an angle (call it x)whose cos=(-2π/5)
so, cosx=(-2π/5)
no solution(-2π/5)<-1.255..
domain:(-1 < cosx < 1)
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