Question 810654: Write as a single logarithm
a) (-2/3) log(base 5) 5m^2 + (1/2)log(base 5) 25m^2
Can you please help me out? Thanks so much in advance Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Write as a single logarithm
a) (-2/3) log(base 5) 5m^2 + (1/2)log(base 5) 25m^2
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(-2/3)log5(5m^2) + (1/2)log5(25m^2)
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= log5(5m^2)^(-2/3) + log5(25m^2)^(1/2)
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= log5(5m)^(-4/3) + log5(5m)
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= log5[(5m)^(-4/3)*(5m)]
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= log5[5m)^(-1/3)]
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Cheers,
Stan H.
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