SOLUTION: Find the equation of a circle having it's diameter the line segment joining the points (3,7) and (-5,1). Can you please help me out? Thanks so much in advance

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Find the equation of a circle having it's diameter the line segment joining the points (3,7) and (-5,1). Can you please help me out? Thanks so much in advance      Log On


   



Question 810651: Find the equation of a circle having it's diameter the line segment joining the points (3,7) and (-5,1).
Can you please help me out? Thanks so much in advance

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of a circle having it's diameter the line segment joining the points (3,7) and (-5,1).
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Find the midpoint (center of the circle).
x = (3+-5)/2 = -1
y = (7+1)/2 = 4
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Center is (-1,4)
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Find the radius (distance from end point to center):
r = sqrt[(3--1)^2+(7-4)^2] = sqrt[16+9] = 5
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Circle Equation:
(x+1)^2 + (y-4)^2 = 5^2
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Cheers,
Stan H.
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