SOLUTION: A new game show requires a playing field with a perimeter of
54 yards and length 3 yards less than twice the width. What are
the dimensions?
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54 yards and length 3 yards less than twice the width. What are
the dimensions?
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Question 810614: A new game show requires a playing field with a perimeter of
54 yards and length 3 yards less than twice the width. What are
the dimensions? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! 54 = 2L + 2W
L = 2W - 3
---
54 = 2L + 2W
54 = 2(2W - 3) + 2W
54 = 4W - 6 + 2W
60 = 6W
---
W = 10
L = 17
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