SOLUTION: Completing the Square and identify the curve as a parabola, hyperbola, ellipse, or a circle. x^2 + y^2 – 12x- 22y+ 142= 0

Algebra ->  Graphs -> SOLUTION: Completing the Square and identify the curve as a parabola, hyperbola, ellipse, or a circle. x^2 + y^2 – 12x- 22y+ 142= 0      Log On


   

Question 810613: Completing the Square and identify the curve as a parabola, hyperbola, ellipse, or a circle.
x^2 + y^2 – 12x- 22y+ 142= 0
Found 2 solutions by MathLover1, richwmiller:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+y%5E2+-12x-22y%2B+142=+0...first group like terms

%28x%5E2-12x%29%2B+%28y%5E2-22y%29%2B+142=+0
%28x%5E2-12x%2B%28_%29%29-%28_%29%2B%28y%5E2-22y%2B%28_%29%29-%28_%29%2B142=+0....complete the square
%28x%5E2-12x%2B36%29-36%2B+%28y%5E2-22y%2B121%29-121%2B+142=+0
%28x-6%29%5E2%2B%28y-11%29%5E2-36-121%2B142+=+0
%28x-6%29%5E2%2B%28y-11%29%5E2-15+=+0
%28x-6%29%5E2%2B%28y-11%29%5E2=15....=> so, this is a circle with center at (6,11) and radius sqrt%2815%29=3.9



Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
circle
(x-6)^2+(y-11)^2=15
circle with center at 6, 11 radius sqrt(15)