SOLUTION: express the following using one log a.log x + log 4 – log 2 b.2log x + log 5 + log 2 c. 3 log x + 2 log x + log 100 solve a. log (x + 4) + log 5 = 2 b. log3(2x + 1) =

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: express the following using one log a.log x + log 4 – log 2 b.2log x + log 5 + log 2 c. 3 log x + 2 log x + log 100 solve a. log (x + 4) + log 5 = 2 b. log3(2x + 1) =      Log On


   



Question 810594: express the following using one log
a.log x + log 4 – log 2
b.2log x + log 5 + log 2
c. 3 log x + 2 log x + log 100

solve
a. log (x + 4) + log 5 = 2
b. log3(2x + 1) = 2

Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
A couple things to mention before i do these problems.
if there is a number before the log, it is an expontent of the number being logged. 2log3=log3%5E2
2 log properties to keep in mind are the multiplication and division properties.
The log of a product is the sum of the logs.
The log of a quotient is the differnce of the logs.
logA%2BlogB=log%28AB%29
logA-logB=log%28A%2FB%29
Just remember if the log is positive it going on top of the fraction. if the log is negative it goes on the bottom. This will help in some future problems.

1
logx%2Blog4-log2
log%284x%2F2%29

2
2logx%2Blog5%2Blog2
logx%5E2%2Blog5%2Blog2
log%28x%5E2%2A5%2A2%29
log%2810x%5E2%29

3
3logx%2B2logx%2Blog100
logx%5E3%2Blogx%5E2%2Blog100
log%28x%5E3%2Ax%5E2%2A100%29
log%28100x%5E5%29

When it asks you to solve the log, you want to find the value of x. For the below proplems we will exponentiate the logs. this means will take the base and raise it to the answer and make it equal to the number being logged.
log%28a%2Cc%29=b
a%5Eb=c
Some examples:
log%283%2C27%29=x
3%5Ex=27
logx=2
10%5E2=x

1
log%28x%2B4%29%2Blog5=2
log%285%28x%2B4%29%29=2
10%5E2=5%28x%2B4%29
100=5x%2B20
5x=80
x=16

2
log%283%2C2x%2B1%29=2
3%5E2=2x%2B1
9=2x%2B1
8=2x
x=4